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c语言简单扫雷,用c语言写扫雷

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C语言编简单的扫雷

给你一个完整的扫雷源码

#include conio.h

#include graphics.h

#include stdio.h

#include stdlib.h

#include time.h

#include ctype.h

#include "mouse.c"

#define YES 1

#define NO 0

#define XPX 15 /* X pixels by square */

#define YPX 15 /* Y pixels by square */

#define DEFCX 30 /* Default number of squares */

#define DEFCY 28

#define MINE 255-'0' /* So that when it prints, it prints char 0xff */

#define STSQUARE struct stsquare

STSQUARE {

unsigned char value; /* Number of mines in the surround squares */

unsigned char sqopen; /* Square is open */

unsigned char sqpress; /* Square is pressed */

unsigned char sqmark; /* Square is marked */

} *psquare;

#define value(x,y) (psquare+(x)*ncy+(y))-value

#define sqopen(x,y) (psquare+(x)*ncy+(y))-sqopen

#define sqpress(x,y) (psquare+(x)*ncy+(y))-sqpress

#define sqmark(x,y) (psquare+(x)*ncy+(y))-sqmark

int XST, /* Offset of first pixel X */

YST,

ncx, /* Number of squares in X */

ncy,

cmines, /* Mines discovered */

initmines, /* Number of initial mines */

sqclosed, /* Squares still closed */

maxy; /* Max. number of y pixels of the screen */

void Graph_init(void);

void Read_param(int argc, char *argv[]);

void Set_mines(int nminas);

void Set_square(int x, int y, int status);

void Mouse_set(void);

void Draw_squares(void);

int Do_all(void);

void Blow_up(void);

void Open_square(int x, int y);

int Open_near_squares(int x, int y);

/************************************************************************/

void main(int argc, char *argv[])

{

if (!mouse_reset()) {

cputs(" ERROR: I can't find a mouse driver\r\n");

exit(2);

}

Graph_init();

Read_param(argc, argv);

Mouse_set();

do {

randomize();

cleardevice();

Set_mines(cmines=initmines);

mouse_enable();

Draw_squares();

}

while (Do_all() != '\x1b');

closegraph();

}

/*************************************************************************

* *

* F U N C T I O N S *

* *

*************************************************************************/

/*----------------------------------------------------------------------*/

void Graph_init(void)

{

int graphdriver=DETECT, graphmode, errorcode;

if(errorcode 0) {

cprintf("\n\rGraphics System Error: %s\n",grapherrormsg(errorcode));

exit(98);

}

initgraph(graphdriver, graphmode, "");

errorcode=graphresult();

if(errorcode!=grOk) {

printf(" Graphics System Error: %s\n",grapherrormsg(errorcode));

exit(98);

}

maxy=getmaxy();

} /* Graph_init */

/*----------------------------------------------------------------------*/

void Read_param(int argc, char *argv[])

{

int x, y, m;

x=y=m=0;

if (argc!=1) {

if (!isdigit(*argv[1])) {

closegraph();

cprintf("Usage is: %s [x] [y] [m]\r\n\n"

"Where x is the horizontal size\r\n"

" y is the vertical size\r\n"

" m is the number of mines\r\n\n"

" Left mouse button: Open the square\r\n"

"Right mouse button: Mark the square\r\n"

" -The first time puts a 'mine' mark\r\n"

" -The second time puts a 'possible "

"mine' mark\r\n"

" -The third time unmarks the square\r\n"

"Left+Right buttons: Open the surrounded squares only if "

"the count of mines\r\n"

" is equal to the number in the square",argv[0]);

exit (1);

}

switch (argc) {

case 4: m=atoi(argv[3]);

case 3: y=atoi(argv[2]);

case 2: x=atoi(argv[1]);

}

}

XST=100;

ncx=DEFCX;

if (maxy==479) {

YST=30;

ncy=DEFCY;

}

else {

YST=25;

ncy=20;

}

if (x0 xncx)

ncx=x;

if (y0 yncy) {

YST+=((ncy-y)*YPX)1;

ncy=y;

}

initmines= m ? m : ncx*ncy*4/25; /* There are about 16% of mines */

if (((void near*)psquare=calloc(ncx*ncy, sizeof(STSQUARE)))==NULL) {

closegraph();

cputs("ERROR: Not enought memory");

exit(3);

}

} /* Read_param */

/*----------------------------------------------------------------------*/

void Set_mines(int nminas)

{

C语言 扫雷

#includestdio.h

int main(void)

{

    char plat[100][100];  //雷的地图

    char plat_new[100][100];  //数字映射图

    int n, m;  //存储行、列数

    int in, im;

    int mark = 0;  //记录该点附近8个坐标雷的总数

    int j = 1;

 

    scanf("%d %d", n, m);

    getchar();  //消除回车符的影响

 

    do {

        if (n == 0  m == 0)

            break;

 

        for (in = 0; in  n; in++)

        {

            for (im = 0; im  m; im++)

            {

                scanf("%c", plat[in][im]);

            }

            getchar();

        }

 

        for (in = 0; in  n; in++)

            for (im = 0; im  m; im++)

            {

                if (plat[in][im] == '*')  /*该点有雷,无需检测*/

                {

                    plat_new[in][im]= plat[in][im];

                    continue;

                }

 

                if (in - 1 = 0)  //检测上面3个点的雷数

                {

                    if (plat[in - 1][im] == '*')

                        mark++;

 

                    if (im - 1 = 0  plat[in -1][im - 1] == '*')

                        mark++;

 

                    if (im + 1  mplat[in -1][im + 1] == '*')

                        mark++;

                }

 

                if (im - 1 = 0  plat[in][im- 1] == '*')  //检测左右两个点的雷数

                    mark++;

                if (im + 1  m  plat[in][im+ 1] == '*')

                    mark++;

 

                if (in + 1  n)  //检测下面3个点的雷数

                {

                    if (plat[in + 1][im] == '*')

                        mark++;

 

                    if (im - 1 = 0  plat[in +1][im - 1] == '*')

                        mark++;

 

                    if (im + 1  mplat[in +1][im + 1] == '*')

                        mark++;

                }

 

                switch (mark)

                {

                case 0:plat_new[in][im] = '0'; break;

                case 1:plat_new[in][im] = '1'; break;

                case 2:plat_new[in][im] = '2'; break;

                case 3:plat_new[in][im] = '3'; break;

                case 4:plat_new[in][im] = '4'; break;

                case 5:plat_new[in][im] = '5'; break;

                case 6:plat_new[in][im] = '6'; break;

                case 7:plat_new[in][im] = '7'; break;

                case 8:plat_new[in][im] = '8'; break;

                }

                mark = 0;  //重置雷数

            }

        if (j != 1)

            putchar('\n');

        printf("Field#%d:\n", j);

 

        for (in = 0; in  n; in++)  //打印数字地图

        {

            for (im = 0; im  m; im++)

            {

                printf("%c", plat_new[in][im]);

            }

            if(in!=n-1)

            putchar('\n');

        }

        scanf("%d %d", n, m);

        getchar();

        j++;

    } while (1);

    return 0;

}

C语言扫雷怎么实现?

点击(x,y)

{

如果(x,y)格子不存在,return

如果是炸弹,GG

如果已经翻开,return

如果周围有雷,显示雷数量,并标记翻开

否则

{

显示空,并标记翻开

点击(x-1,y-1)....点击(x+1,y+1)共8个

}

}

基本思路是这样

C语言扫雷游戏源代码

"扫雷"小游戏C代码

#includestdio.h

#includemath.h

#includetime.h

#includestdlib.h

main( )

{char a[102][102],b[102][102],c[102][102],w;

int i,j;  /*循环变量*/

int x,y,z[999];  /*雷的位置*/

int t,s;  /*标记*/

int m,n,lei;  /*计数*/

int u,v;  /*输入*/

int hang,lie,ge,mo;  /*自定义变量*/

srand((int)time(NULL));  /*启动随机数发生器*/

leb1:  /*选择模式*/

printf("\n   请选择模式:\n   1.标准  2.自定义\n");

scanf("%d",mo);

if(mo==2)  /*若选择自定义模式,要输入三个参数*/

{do

{t=0; printf("请输入\n行数 列数 雷的个数\n");

scanf("%d%d%d",hang,lie,ge);

if(hang2){printf("行数太少\n"); t=1;}

if(hang100){printf("行数太多\n");t=1;}

if(lie2){printf("列数太少\n");t=1;}

if(lie100){printf("列数太多\n");t=1;}

if(ge1){printf("至少要有一个雷\n");t=1;}

if(ge=(hang*lie)){printf("雷太多了\n");t=1;}

}while(t==1);

}

else{hang=10,lie=10,ge=10;}  /*否则就是选择了标准模式(默认参数)*/

for(i=1;i=ge;i=i+1)  /*确定雷的位置*/

{do

{t=0; z[i]=rand( )%(hang*lie);

for(j=1;ji;j=j+1){if(z[i]==z[j]) t=1;}

}while(t==1);

}

for(i=0;i=hang+1;i=i+1)  /*初始化a,b,c*/

{for(j=0;j=lie+1;j=j+1) {a[i][j]='1'; b[i][j]='1'; c[i][j]='0';} }

for(i=1;i=hang;i=i+1)

{for(j=1;j=lie;j=j+1) {a[i][j]='+';} }

for(i=1;i=ge;i=i+1)  /*把雷放入c*/

{x=z[i]/lie+1; y=z[i]%lie+1; c[x][y]='#';}

for(i=1;i=hang;i=i+1)  /*计算b中数字*/

{for(j=1;j=lie;j=j+1)

{m=48;

if(c[i-1][j-1]=='#')m=m+1; if(c[i][j-1]=='#')m=m+1;

if(c[i-1][j]=='#')m=m+1;  if(c[i+1][j+1]=='#')m=m+1;

if(c[i][j+1]=='#')m=m+1;  if(c[i+1][j]=='#')m=m+1;

if(c[i+1][j-1]=='#')m=m+1; if(c[i-1][j+1]=='#')m=m+1;

b[i][j]=m;

}

}

for(i=1;i=ge;i=i+1)  /*把雷放入b中*/

{x=z[i]/lie+1; y=z[i]%lie+1; b[x][y]='#';}

lei=ge;  /*以下是游戏设计*/

do

{leb2:  /*输出*/

system("cls");printf("\n\n\n\n");

printf("    ");

for(i=1;i=lie;i=i+1)

{w=(i-1)/10+48; printf("%c",w);

w=(i-1)%10+48; printf("%c  ",w);

}

printf("\n   |");

for(i=1;i=lie;i=i+1){printf("---|");}

printf("\n");

for(i=1;i=hang;i=i+1)

{w=(i-1)/10+48; printf("%c",w);

w=(i-1)%10+48; printf("%c |",w);

for(j=1;j=lie;j=j+1)

{if(a[i][j]=='0')printf("   |");

else printf(" %c |",a[i][j]);

}

if(i==2)printf(" 剩余雷个数");

if(i==3)printf(" %d",lei);

printf("\n   |");

for(j=1;j=lie;j=j+1){printf("---|");}

printf("\n");

}

scanf("%d%c%d",u,w,v);  /*输入*/

u=u+1,v=v+1;

if(w!='#'a[u][v]=='@')

goto leb2;

if(w=='#')

{if(a[u][v]=='+'){a[u][v]='@'; lei=lei-1;}

else if(a[u][v]=='@'){a[u][v]='?'; lei=lei+1;}

else if(a[u][v]=='?'){a[u][v]='+';}

goto leb2;

}

a[u][v]=b[u][v];

leb3:  /*打开0区*/

t=0;

if(a[u][v]=='0')

{for(i=1;i=hang;i=i+1)

{for(j=1;j=lie;j=j+1)

{s=0;

if(a[i-1][j-1]=='0')s=1; if(a[i-1][j+1]=='0')s=1;

if(a[i-1][j]=='0')s=1;  if(a[i+1][j-1]=='0')s=1;

if(a[i+1][j+1]=='0')s=1; if(a[i+1][j]=='0')s=1;

if(a[i][j-1]=='0')s=1;  if(a[i][j+1]=='0')s=1;

if(s==1)a[i][j]=b[i][j];

}

}

for(i=1;i=hang;i=i+1)

{for(j=lie;j=1;j=j-1)

{s=0;

if(a[i-1][j-1]=='0')s=1; if(a[i-1][j+1]=='0')s=1;

if(a[i-1][j]=='0')s=1;  if(a[i+1][j-1]=='0')s=1;

if(a[i+1][j+1]=='0')s=1; if(a[i+1][j]=='0')s=1;

if(a[i][j-1]=='0')s=1;   if(a[i][j+1]=='0')s=1;

if(s==1)a[i][j]=b[i][j];

}

}

for(i=hang;i=1;i=i-1)

{for(j=1;j=lie;j=j+1)

{s=0;

if(a[i-1][j-1]=='0')s=1; if(a[i-1][j+1]=='0')s=1;

if(a[i-1][j]=='0')s=1;  if(a[i+1][j-1]=='0')s=1;

if(a[i+1][j+1]=='0')s=1; if(a[i+1][j]=='0')s=1;

if(a[i][j-1]=='0')s=1;  if(a[i][j+1]=='0')s=1;

if(s==1)a[i][j]=b[i][j];

}

}

for(i=hang;i=1;i=i-1)

{for(j=lie;j=1;j=j-1)

{s=0;

if(a[i-1][j-1]=='0')s=1; if(a[i-1][j+1]=='0')s=1;

if(a[i-1][j]=='0')s=1;  if(a[i+1][j-1]=='0')s=1;

if(a[i+1][j+1]=='0')s=1;if(a[i+1][j]=='0')s=1;

if(a[i][j-1]=='0')s=1;  if(a[i][j+1]=='0')s=1;

if(s==1)a[i][j]=b[i][j];

}

}

for(i=1;i=hang;i=i+1)  /*检测0区*/

{for(j=1;j=lie;j=j+1)

{if(a[i][j]=='0')

{if(a[i-1][j-1]=='+'||a[i-1][j-1]=='@'||a[i-1][j-1]=='?')t=1;

if(a[i-1][j+1]=='+'||a[i-1][j+1]=='@'||a[i-1][j+1]=='?')t=1;

if(a[i+1][j-1]=='+'||a[i+1][j-1]=='@'||a[i+1][j-1]=='?')t=1;

if(a[i+1][j+1]=='+'||a[i+1][j+1]=='@'||a[i+1][j+1]=='?')t=1;

if(a[i+1][j]=='+'||a[i+1][j]=='@'||a[i+1][j]=='?')t=1;

if(a[i][j+1]=='+'||a[i][j+1]=='@'||a[i][j+1]=='?')t=1;

if(a[i][j-1]=='+'||a[i][j-1]=='@'||a[i][j-1]=='?')t=1;

if(a[i-1][j]=='+'||a[i-1][j]=='@'||a[i-1][j]=='?')t=1;

}

}

}

if(t==1)goto leb3;

}

n=0;  /*检查结束*/

for(i=1;i=hang;i=i+1)

{for(j=1;j=lie;j=j+1)

{if(a[i][j]!='+'a[i][j]!='@'a[i][j]!='?')n=n+1;}

}

}

while(a[u][v]!='#'n!=(hang*lie-ge));

for(i=1;i=ge;i=i+1)  /*游戏结束*/

{x=z[i]/lie+1; y=z[i]%lie+1; a[x][y]='#'; }

printf("    ");

for(i=1;i=lie;i=i+1)

{w=(i-1)/10+48; printf("%c",w);

w=(i-1)%10+48; printf("%c  ",w);

}

printf("\n   |");

for(i=1;i=lie;i=i+1){printf("---|");}

printf("\n");

for(i=1;i=hang;i=i+1)

{w=(i-1)/10+48; printf("%c",w);

w=(i-1)%10+48; printf("%c |",w);

for(j=1;j=lie;j=j+1)

{if(a[i][j]=='0')printf(" |");

else  printf(" %c |",a[i][j]);

}

if(i==2)printf(" 剩余雷个数");

if(i==3)printf(" %d",lei); printf("\n   |");

for(j=1;j=lie;j=j+1) {printf("---|");}

printf("\n");

}

if(n==(hang*lie-ge)) printf("你成功了!\n");

else printf("    游戏结束!\n");

printf("    重玩请输入1\n");

t=0;

scanf("%d",t);

if(t==1)goto leb1;

}

/*注:在DEV c++上运行通过。行号和列号都从0开始,比如要确定第0行第9列不是“雷”,就在0和9中间加入一个字母,可以输入【0a9】三个字符再按回车键。3行7列不是雷,则输入【3a7】回车;第8行第5列是雷,就输入【8#5】回车,9行0列是雷则输入【9#0】并回车*/

扫雷C语言

#include stdio.h

#define N 40

int a[N][2];

int num;

void display()

{

for(int j=0; j num; j++)

{

printf("%d ", a[j][1]);

}

printf("\n");

}

void test(int i)

{

if(i == num)

{

int j;

int flag = 1;

if(a[0][1]+a[1][1]!=a[0][0]a[num-1][1]+a[num-2][1]!=a[num-1][0])

{

}

for(j = 1; j num - 1; j++)

{

if(a[j-1][1] + a[j][1] + a[j+1][1] != a[j][0])

flag = 0;

}

if(flag)

display();

}

for(; i num; i++)

{

if(a[i][1] == 0)

{

if(i == 0)

{

if(a[i][1]+a[i+1][1] != a[i][0])

{

a[i][1] = 1;

test(i+1);

a[i][1] = 0;

}

}

if(i 0)

{

if(a[i-1][1] + a[i][1] + a[i+1][1] != a[i][0])

{

a[i][1] = 1;

test(i+1);

a[i][1] = 0;

}

}

}

}

}

int main()

{

int i;

printf("输入个数:\n");

scanf("%d",num);

printf("输入数据(0~3):\n");

for(i = 0; i num; i++)

{

scanf("%d",a[i][0]);

a[i][1]=0;

}

for(i = 1; i num - 1; i++)

{

if(a[i][0] == 3)

{

a[i-1][1] = 1;

a[i][1] = 1;

a[i+1][1] = 1;

}

}

test(0);

}

算法思想:

1、如果有输入数字是3则输出数字中对应上中下都必为1

2、输出数组中只有为0的才能为1;

3、用回溯法判断成立条件,成功则输出。

如何用C语言编程 扫雷!~

俄罗斯方快

扫雷

#includestdio.h

#includegraphics.h

#includestdlib.h

struct list

{

int x;

int y;

int num;

int bomb;

int wa;

};

struct list di[10][10];

int currentx=210;

int currenty=130;

void initxy(void)

{

int i,j;

for(i=0;i=9;i++)

for(j=0;j=9;j++)

{

di[j].x=i*20+200;

di[j].y=j*20+120;

di[j].wa=0;

di[j].bomb=0;

}

}

void initmu(void)

{

int i,j;

setcolor(2);

rectangle(200,120,400,320);

rectangle(190,110,410,330);

setfillstyle(8,14);

floodfill(191,111,2);

for(i=0;i=9;i++)

for(j=0;j=9;j++)

rectangle(di[j].x,di[j].y,di[j].x+19,di[j].y+19);

outtextxy(450,200,"press 'enter' to kick");

outtextxy(450,250,"press '\' to mark");

}

void randbomb(void)

{

int k;

int i,j;

randomize();

for(i=0;i=9;i++)

for(j=0;j=9;j++)

{

k=random(5);

if(k==2)

di[j].bomb=1;

}

}

void jisuan(void)

{

int k=0;

int i,j;

for(i=0;i=9;i++)

for(j=0;j=9;j++)

{

if(ijdi[i-1][j-1].bomb)

k=k+1;

if(idi[i-1][j].bomb)

k=k+1;

if(jdi[j-1].bomb)

k=k+1;

if(i=8di[i+1][j].bomb)

k=k+1;

if(j=8di[j+1].bomb)

k=k+1;

if(i=8j=8di[i+1][j+1].bomb)

k=k+1;

if(ij=8di[i-1][j+1].bomb)

k=k+1;

if(i=8jdi[i+1][j-1].bomb)

k=k+1;

di[j].num=k;

k=0;

}

}

void xianbomb(void)

{

int i,j;

char biaoji[2];

char znum[2];

biaoji[0]=1;

biaoji[1]=NULL;

for(i=0;i=9;i++)

for(j=0;j=9;j++)

{

if(di[j].bomb==1)

outtextxy(di[j].x+2,di[j].y+2,biaoji);

else

{

itoa(di[j].num,znum,10);

setfillstyle(1,0);

bar(i*20+202,j*20+122,i*20+218,j*20+138);

outtextxy(i*20+202,j*20+122,znum);

}

}

}

void move(void)

{

int key;

key=bioskey(1);

if(key)

key=bioskey(0);

if(key==0x4800)

{

if(currenty130)

{

setcolor(0);

circle(currentx,currenty,5);

currenty-=20;

setcolor(4);

circle(currentx,currenty,5);

}

else

{

setcolor(0);

circle(currentx,currenty,5);

currenty=310;

setcolor(4);

circle(currentx,currenty,5);

}

}

if(key==0x4b00)

{

if(currentx210)

{

setcolor(0);

circle(currentx,currenty,5);

currentx-=20;

setcolor(4);

circle(currentx,currenty,5);

}

else

{

setcolor(0);

circle(currentx,currenty,5);

currentx=390;

setcolor(4);

circle(currentx,currenty,5);

}

}

if(key==0x4d00)

{

if(currentx390)

{

setcolor(0);

circle(currentx,currenty,5);

currentx+=20;

setcolor(4);

circle(currentx,currenty,5);

}

else

{

setcolor(0);

circle(currentx,currenty,5);

currentx=210;

setcolor(4);

circle(currentx,currenty,5);

}

}

if(key==0x5000)

{

if(currenty310)

{

setcolor(0);

circle(currentx,currenty,5);

currenty+=20;

setcolor(4);

circle(currentx,currenty,5);

}

else

{

setcolor(0);

circle(currentx,currenty,5);

currenty=130;

setcolor(4);

circle(currentx,currenty,5);

}

}

if(key==0x1c0d)

{

int i,j;

char snum[2];

snum[0]=NULL;

snum[1]=NULL;

i=(currentx-210)/20;

j=(currenty-130)/20;

if(di[j].bomb==1)

{

outtextxy(100,100,"game over");

xianbomb();

sleep(2);

exit(0);

}

if(di[j].bomb==0)

{

di[j].wa=1;

setfillstyle(1,0);

bar(currentx-8,currenty-8,currentx+8,currenty+8);

setcolor(15);

itoa(di[j].num,snum,10);

outtextxy(currentx-8,currenty-8,snum);

setcolor(4);

circle(currentx,currenty,5);

}

}

if(key==0x2b5c)

{

char biaoji[2];

biaoji[0]=1;

biaoji[1]=NULL;

setcolor(0);

bar(currentx-8,currenty-8,currentx+8,currenty+8);

setcolor(4);

outtextxy(currentx-8,currenty-8,biaoji);

circle(currentx,currenty,5);

}

}

void success(void)

{

int k=1;

int i,j;

for(i=0;i=9;i++)

for(j=0;j=9;j++)

if(di[j].bomb==0di[j].wa==0)

k=0;

if(k==1)

{

outtextxy(100,100,"success good");

xianbomb();

sleep(2);

exit(0);

}

}

void main(void)

{

int gd=DETECT,gm;

initgraph(gd,gm,"");

initxy();

initmu();

randbomb();

jisuan();

setcolor(4);

circle(210,130,5);

while(1)

{

move();

success();

}

}