#c086js的简单介绍 更新:2022-11-20 16:18
本文目录一览:
- a=[[a,b,c],[a,d,e][b,c,d]],JS把二维数组内每个数组第一个相等的数组合并
- [C语言和 JavaScript哪个简单?好学好掌握](#C语言和 JavaScript哪个简单?好学好掌握)
- [求解密(function(){function Aa(a,b,c)开头JS及解密工具或代码](#求解密(function(){function Aa(a,b,c)开头JS及解密工具或代码)
- C语言的编程题用js怎么写:输入三个整数,按从大到小的顺序输出
- c:when判断语句中可以写js或者JAVA的代码获取的值吗?
a=[[a,b,c],[a,d,e][b,c,d]],JS把二维数组内每个数组第一个相等的数组合并
var a=[['a','b','c'],['a','d','e'],['b','c','d']];
var result = [];
var getIndex = function(result, arr) {
for (var i = 0; i < result.length; i++) {
if (result[i] && result[i][0] == arr[0]) {
return i;
}
}
return -1;
}
var merge = function(arr1, arr2) {
for (var i = 1; i < arr2.length; i++) {
arr1.push(arr2[i]);
}
}
for (var i = 0; i < a.length; i++) {
var index = getIndex(result, a[i]);
if (index >= 0) {
merge(result[index], a[i]);
} else {
result.push(a[i]);
}
}
return result;
C语言和 JavaScript哪个简单?好学好掌握
程序语言在底层实现方面很多都是共同的,C语言适用范围广,底层的一些东西基本上都用C,好学但不容易深入。 javascript看似简单,但不容易掌握。
求解密(function(){function Aa(a,b,c)开头JS及解密工具或代码
(function() {
function Aa(a, b, c) {
var d;
b = b.toLowerCase();
return (d = a.__allListeners || c && (a.__allListeners = {})) && (d[b] || c && (d[b] = []))
}
function Ba(a, b, c, d, e, g) {
d = d && a[b];
var h;
for (!d && (d = a[c]); !d && (h = (h || a).parentNode);) {
if ("BODY" == h.tagName || g && !g(h)) return null;
d = h[c]
}
return d && e && !e(d) ? Ba(d, b, c, !1, e) : d
}
UEDITOR_CONFIG = window.UEDITOR_CONFIG || {};
var q = window.baidu || {};
window.baidu = q;
window.UE = q.editor = {};
UE.plugins = {};
UE.commands = {};
UE.instants = {};
UE.I18N = {};
UE.version = "1.2.6.0";
var R = UE.dom = {},
Bc = UE,
U = navigator.userAgent.toLowerCase(),
Ca = window.opera,
B = {
ie: !!window.ActiveXObject,
opera: !!Ca && Ca.version,
webkit: -1 < U.indexOf(" applewebkit/"),
mac: -1 < U.indexOf("macintosh"),
quirks: "BackCompat" == document.compatMode
};
B.gecko = "Gecko" == navigator.product && !B.webkit && !B.opera;
var N = 0;
B.ie && (N = parseFloat(U.match(/msie (\d+)/)[1]), B.ie9Compat = 9 == document.documentMode, B.ie8 = !!document.documentMode, B.ie8Compat = 8 == document.documentMode, B.ie7Compat = 7 == N && !document.documentMode || 7 == document.documentMode, B.ie6Compat = 7 > N || B.quirks);
if (B.gecko) {
var Z = U.match(/rv:([\d\.]+)/);
Z && (Z = Z[1].split("."), N = 1E4 * Z[0] + 100 * (Z[1] || 0) + 1 * (Z[2] || 0))
}
/chrome\/(\d+\.\d)/i.test(U) && (B.chrome = +RegExp.$1);
/(\d+\.\d)?(?:\.\d)?\s+safari\/?(\d+\.\d+)?/i.test(U) && !/chrome/i.test(U) && (B.safari = +(RegExp.$1 || RegExp.$2));
B.opera && (N = parseFloat(Ca.version()));
B.webkit && (N = parseFloat(U.match(/ applewebkit\/(\d+)/)[1]));
B.version = N;
B.isCompatible = !B.mobile
})();
C语言的编程题用js怎么写:输入三个整数,按从大到小的顺序输出
参考代码:
#include "stdio.h"
int main() {
int x,y,z,max,min;
scanf("%d%d%d",&x,&y,&z);
if(x>y){
max=x;
min=y;
}
if(z>max) max=z;
if(min>z) min=z;
y=x+y+z-max-min;
x=max;
z=min;
printf("从大到小排序:%d %d %d\n",x,y,z);
}
运行结果:
3 1 2
从大到小排序:3 2 1
扩展资料 利用指针变量,用函数实现将3个整数按从大到小的顺序输出。 解:程序:
#include<stdio.h>
void swap(int *ptr1, int *ptr2) {
int temp = *ptr1;
*ptr1 = *ptr2;
*ptr2 = temp;
}
void exchange(int *q1, int *q2, int *q3) {
void swap(int *ptr1, int *ptr2);
if (*q1 < *q2) {
swap(q1, q2);
}
if (*q1 < *q3) {
swap(q1, q3);
}
if (*q2 < *q3) {
swap(q2, q3);
}
}
int main() {
void exchange(int *q1, int *q2, int *q3);
int *p1, *p2, *p3, a, b,c;
printf("please enter three integer numbers:");
scanf("%d,%d,%d",&a,&b,&c);
p1 = &a;
p2 = &b;
p3 = &c;
exchange(p1, p2, p3);
printf("The order is:%d,%d,%d\n",a,b,c);
return 0;
}
结果:
please enter three integer numbers:7,-9,666
The order is:666,7,-9
请按任意键继续. . .
c:when判断语句中可以写js或者JAVA的代码获取的值吗?
先弄清楚 标签是服务器端脚本, js是客户端脚本。 两者执行时机不同,没办法互用