编写一个 Python 程序来查找元组中所有项目的总和。这里,我们使用 Tuple sum 函数返回所有 Tuple 项的总和。
# Tuple Sum of All Items
numTuple = (20, 40, 65, 75, 80, 220)
print("Tuple Items = ", numTuple)
tupleSum = sum(numTuple)
print("\nThe Sum of numTuple Tuple Items = ", tupleSum)
Tuple Items = (20, 40, 65, 75, 80, 220)
The Sum of numTuple Tuple Items = 500
寻找元组项之和的 Python 程序
在这个 Python 示例中,for 循环(用于 numTuple 中的 tup)迭代所有元组项。在循环(tupleSum = tupleSum + tup)中,我们将每个元组项添加到 tupleSum 中,并打印相同的内容。
# Tuple Sum of All Items
numTuple = (11, 22, 33, 44, 55, 66, 77, 88, 99)
print("Odd Tuple Items = ", numTuple)
tupleSum = 0
for tup in numTuple:
tupleSum = tupleSum + tup
print("\nThe Sum of numTuple Tuple Items = ", tupleSum)
Odd Tuple Items = (11, 22, 33, 44, 55, 66, 77, 88, 99)
The Sum of numTuple Tuple Items = 495
Python 程序使用 While 循环计算所有元组项的总和。
# Tuple Sum of All Items
numTuple = (25, 45, 65, 75, 95, 125, 256, 725)
print("Odd Tuple Items = ", numTuple)
tupleSum = 0
i = 0
while (i < len(numTuple)):
tupleSum = tupleSum + numTuple[i]
i = i + 1
print("\nThe Sum of numTuple Tuple Items = ", tupleSum)
Odd Tuple Items = (25, 45, 65, 75, 95, 125, 256, 725)
The Sum of numTuple Tuple Items = 1411
在这个 Python Tuple 示例中,我们创建了一个 sumOfTupleItems(numTuple)函数,该函数将计算并返回所有 tuple 项的总和。
# Tuple Sum
def sumOfTupleItems(numTuple):
tupleSum = 0
for tup in numTuple:
tupleSum = tupleSum + tup
return tupleSum
numTuple = (16, 31, 24, 98, 123, 78, 56, 67, 22)
print("Tuple Items = ", numTuple)
tSum = sumOfTupleItems(numTuple)
print("\nThe Sum of numTuple Tuple Items = ", tSum)