写一个 Python 程序,用 While 循环、For 循环和函数的例子来求N
个自然数的和与均值。
用 For 循环求N
个自然数的和与均值的 Python 程序
该程序允许用户输入任意整数值。接下来,这个 Python 程序使用 For 循环计算从 1 到用户指定值的自然数的总和和平均值。
# Python Program to find Sum and Average of N Natural Numbers
number = int(input("Please Enter any Number: "))
total = 0
for value in range(1, number + 1):
total = total + value
average = total / number
print("The Sum of Natural Numbers from 1 to {0} = {1}".format(number, total))
print("Average of Natural Numbers from 1 to {0} = {1}".format(number, average))
用于循环输出的自然数的 Python 和与均值
Please Enter any Number: 5
The Sum of Natural Numbers from 1 to 5 = 15
Average of Natural Numbers from 1 to 5 = 3.0
使用 While 循环计算N
个自然数的和与均值的 Python 程序
在这个寻找自然数的和与均值的 Python 程序中,我们将循环的替换为循环的。请参考 C 示例以迭代方式理解这个 Python 代码执行。
# Python Program to find Sum and Average of N Natural Numbers
number = int(input("Please Enter any Number: "))
total = 0
value = 1
while (value <= number):
total = total + value
value = value + 1
average = total / number
print("The Sum of Natural Numbers from 1 to {0} = {1}".format(number, total))
print("Average of Natural Numbers from 1 to {0} = {1}".format(number, average))
Python 使用 while Loop 输出自然数的总和和平均值
Please Enter any Number: 10
The Sum of Natural Numbers from 1 to 10 = 55
Average of Natural Numbers from 1 to 10 = 5.5
用函数计算N
个自然数的和与均值的 Python 程序
在这个寻找自然数的和与均值的 Python 程序中,我们创建了一个新的函数来寻找自然数的和与均值。在这个函数中,我们使用了 If Else 语句
# Python Program to find Sum and Average of N Natural Numbers
def sum_and_avg_of_natural_numbers(num):
if(num == 0):
return num
else:
return (num * (num + 1) / 2)
number = int(input("Please Enter any Number: "))
total = sum_and_avg_of_natural_numbers(number)
average = total / number
print("The Sum of Natural Numbers from 1 to {0} = {1}".format(number, total))
print("Average of Natural Numbers from 1 to {0} = {1}".format(number, average))
Python 使用函数输出自然数的总和和平均值
Please Enter any Number: 100
The Sum of Natural Numbers from 1 to 100 = 5050.0
Average of Natural Numbers from 1 to 100 = 50.5
用递归实现N
个自然数的和与均值的 Python 程序
这个 Python 程序求自然数的和与均值和上面的例子一样,但是这次我们用的是递归。
# Python Program to find Sum and Average of N Natural Numbers
def sum_and_avg_of_natural_numbers(num):
if(num == 0):
return num
else:
return (num + sum_and_avg_of_natural_numbers(num - 1))
number = int(input("Please Enter any Number: "))
total = sum_and_avg_of_natural_numbers(number)
average = total / number
print("The Sum of Natural Numbers from 1 to {0} = {1}".format(number, total))
print("Average of Natural Numbers from 1 to {0} = {1}".format(number, average))