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求JAVA连连看游戏代码
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
public class lianliankan implements ActionListener {
JFrame mainFrame; // 主面板
Container thisContainer;
JPanel centerPanel, southPanel, northPanel; // 子面板
JButton diamondsButton[][] = new JButton[6][5]; // 游戏按钮数组
JButton exitButton, resetButton, newlyButton; // 退出,重列,重新开始按钮
JLabel fractionLable = new JLabel("0"); // 分数标签
JButton firstButton, secondButton; // 分别记录两次被选中的按钮
int grid[][] = new int[8][7]; // 储存游戏按钮位置
static boolean pressInformation = false; // 判断是否有按钮被选中
int x0 = 0, y0 = 0, x = 0, y = 0, fristMsg = 0, secondMsg = 0, validateLV; // 游戏按钮的位置坐标
int i, j, k, n; // 消除方法控制
public void init() {
mainFrame = new JFrame("JKJ连连看");
thisContainer = mainFrame.getContentPane();
thisContainer.setLayout(new BorderLayout());
centerPanel = new JPanel();
southPanel = new JPanel();
northPanel = new JPanel();
thisContainer.add(centerPanel, "Center");
thisContainer.add(southPanel, "South");
thisContainer.add(northPanel, "North");
centerPanel.setLayout(new GridLayout(6, 5));
for (int cols = 0; cols < 6; cols++) {
for (int rows = 0; rows < 5; rows++) {
diamondsButton[cols][rows] = new JButton(String.valueOf(grid[cols + 1][rows + 1]));
diamondsButton[cols][rows].addActionListener(this);
centerPanel.add(diamondsButton[cols][rows]);
}
}
exitButton = new JButton("退出");
exitButton.addActionListener(this);
resetButton = new JButton("重列");
resetButton.addActionListener(this);
newlyButton = new JButton("再来一局");
newlyButton.addActionListener(this);
southPanel.add(exitButton);
southPanel.add(resetButton);
southPanel.add(newlyButton);
fractionLable.setText(String.valueOf(Integer.parseInt(fractionLable.getText())));
northPanel.add(fractionLable);
mainFrame.setBounds(280, 100, 500, 450);
mainFrame.setVisible(true);
}
public void randomBuild() {
int randoms, cols, rows;
for (int twins = 1; twins <= 15; twins++) {
randoms = (int) (Math.random() * 25 + 1);
for (int alike = 1; alike <= 2; alike++) {
cols = (int) (Math.random() * 6 + 1);
rows = (int) (Math.random() * 5 + 1);
while (grid[cols][rows] != 0) {
cols = (int) (Math.random() * 6 + 1);
rows = (int) (Math.random() * 5 + 1);
}
this.grid[cols][rows] = randoms;
}
}
}
public void fraction() {
fractionLable.setText(String.valueOf(Integer.parseInt(fractionLable.getText()) + 100));
}
public void reload() {
int save[] = new int[30];
int n = 0, cols, rows;
int grid[][] = new int[8][7];
for (int i = 0; i <= 6; i++) {
for (int j = 0; j <= 5; j++) {
if (this.grid[i][j] != 0) {
save[n] = this.grid[i][j];
n++;
}
}
}
n = n - 1;
this.grid = grid;
while (n >= 0) {
cols = (int) (Math.random() * 6 + 1);
rows = (int) (Math.random() * 5 + 1);
while (grid[cols][rows] != 0) {
cols = (int) (Math.random() * 6 + 1);
rows = (int) (Math.random() * 5 + 1);
}
this.grid[cols][rows] = save[n];
n--;
}
mainFrame.setVisible(false);
pressInformation = false; // 这里一定要将按钮点击信息归为初始
init();
for (int i = 0; i < 6; i++) {
for (int j = 0; j < 5; j++) {
if (grid[i + 1][j + 1] == 0)
diamondsButton[i][j].setVisible(false);
}
}
}
public void estimateEven(int placeX, int placeY, JButton bz) {
if (pressInformation == false) {
x = placeX;
y = placeY;
secondMsg = grid[x][y];
secondButton = bz;
pressInformation = true;
} else {
x0 = x;
y0 = y;
fristMsg = secondMsg;
firstButton = secondButton;
x = placeX;
y = placeY;
secondMsg = grid[x][y];
secondButton = bz;
if (fristMsg == secondMsg && secondButton != firstButton) {
xiao();
}
}
}
public void estimateEven(int placeX, int placeY, JButton bz) {
if (pressInformation == false) {
x = placeX;
y = placeY;
secondMsg = grid[x][y];
secondButton = bz;
pressInformation = true;
} else {
x0 = x;
y0 = y;
fristMsg = secondMsg;
firstButton = secondButton;
x = placeX;
y = placeY;
secondMsg = grid[x][y];
secondButton = bz;
if (fristMsg == secondMsg && secondButton != firstButton) {
xiao();
}
}
}
public void xiao() { // 相同的情况下能不能消去。仔细分析,不一条条注释
if ((x0 == x && (y0 == y + 1 || y0 == y - 1)) || ((x0 == x + 1 || x0 == x - 1) && (y0 == y))) { // 判断是否相邻
remove();
} else {
for (j = 0; j < 7; j++) {
if (grid[x0][j] == 0) { // 判断第一个按钮同行哪个按钮为空
if (y < j) { // 如果第二个按钮的Y坐标大于空按钮的Y坐标说明第一按钮在第二按钮左边
for (i = y - 1; i >= j; i--) { // 判断第二按钮左侧直到第一按钮中间有没有按钮
if (grid[x][i] != 0) {
k = 0;
break;
} else {
k = 1;
} // K=1说明通过了第一次验证
}
if (k == 1) {
linePassOne();
}
}
if (y > j) { // 如果第二个按钮的Y坐标小于空按钮的Y坐标说明第一按钮在第二按钮右边
for (i = y + 1; i <= j; i++) { // 判断第二按钮左侧直到第一按钮中间有没有按钮
if (grid[x][i] != 0) {
k = 0;
break;
} else {
k = 1;
}
}
if (k == 1) {
linePassOne();
}
}
if (y == j) {
linePassOne();
}
}
}
if (k == 2) {
if (x0 == x) {
remove();
}
if (x0 < x) {
for (n = x0; n <= x - 1; n++) {
if (grid[n][j] != 0) {
k = 0;
break;
}
if (grid[n][j] == 0 && n == x - 1) {
remove();
}
}
}
if (x0 > x) {
for (n = x0; n <= x + 1; n--) {
if (grid[n][j] != 0) {
k = 0;
break;
}
if (grid[n][j] == 0 && n == x + 1) {
remove();
}
}
}
}
}
for (i = 0; i < 8; i++) { // 列
if (grid[i][y0] == 0) {
if (x < i) {
for (j = x - 1; j >= i; j--) {
if (grid[j][y] != 0) {
k = 0;
break;
} else {
k = 1;
}
}
if (k == 1) {
rowPassOne();
}
}
if (x > i) {
for (j = x + 1; j <= i; j++) {
if (grid[j][y] != 0) {
k = 0;
break;
} else {
k = 1;
}
}
if (k == 1) {
rowPassOne();
}
}
if (x == i) {
rowPassOne();
}
}
}
if (k == 2) {
if (y0 == y) {
remove();
}
if (y0 < y) {
for (n = y0; n <= y - 1; n++) {
if (grid[i][n] != 0) {
k = 0;
break;
}
if (grid[i][n] == 0 && n == y - 1) {
remove();
}
}
}
if (y0 > y) {
for (n = y0; n <= y + 1; n--) {
if (grid[i][n] != 0) {
k = 0;
break;
}
if (grid[i][n] == 0 && n == y + 1) {
remove();
}
}
}
}
}
public void linePassOne() {
if (y0 < j) { // 第一按钮同行空按钮在左边
for (i = y0 - 1; i >= j; i--) { // 判断第一按钮同左侧空按钮之间有没按钮
if (grid[x0][i] != 0) {
k = 0;
break;
} else {
k = 2;
} // K=2说明通过了第二次验证
}
}
if (y0 > j) { // 第一按钮同行空按钮在与第二按钮之间
for (i = y0 + 1; i <= j; i++) {
if (grid[x0][i] != 0) {
k = 0;
break;
} else {
k = 2;
}
}
}
}
public void rowPassOne() {
if (x0 < i) {
for (j = x0 - 1; j >= i; j--) {
if (grid[j][y0] != 0) {
k = 0;
break;
} else {
k = 2;
}
}
}
if (x0 > i) {
for (j = x0 + 1; j <= i; j++) {
if (grid[j][y0] != 0) {
k = 0;
break;
} else {
k = 2;
}
}
}
}
public void remove() {
firstButton.setVisible(false);
secondButton.setVisible(false);
fraction();
pressInformation = false;
k = 0;
grid[x0][y0] = 0;
grid[x][y] = 0;
}
public void actionPerformed(ActionEvent e) {
if (e.getSource() == newlyButton) {
int grid[][] = new int[8][7];
this.grid = grid;
randomBuild();
mainFrame.setVisible(false);
pressInformation = false;
init();
}
if (e.getSource() == exitButton)
System.exit(0);
if (e.getSource() == resetButton)
reload();
for (int cols = 0; cols < 6; cols++) {
for (int rows = 0; rows < 5; rows++) {
if (e.getSource() == diamondsButton[cols][rows])
estimateEven(cols + 1, rows + 1, diamondsButton[cols][rows]);
}
}
}
public static void main(String[] args) {
lianliankan llk = new lianliankan();
llk.randomBuild();
llk.init();
}
}
用java语言编写连连看游戏
我以前自己写一个玩的。没有把你要求的功能全部实现,不过你看了后可以改一下就好了。参考一下吧,我给了注解:
package mybase.programe;
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
public class LianLianKan implements ActionListener {
JFrame mainFrame; // 主面板
Container thisContainer;
JPanel centerPanel, southPanel, northPanel; // 子面板
JButton diamondsButton[][] = new JButton[6][5]; // 游戏按钮数组
JButton exitButton, resetButton, newlyButton; // 退出,重列,重新开始按钮
JLabel fractionLable = new JLabel("0"); // 分数标签
JButton firstButton, secondButton; // 分别记录两次被选中的按钮
int grid[][] = new int[8][7]; // 储存游戏按钮位置
static boolean pressInformation = false; // 判断是否有按钮被选中
int x0 = 0, y0 = 0, x = 0, y = 0, fristMsg = 0, secondMsg = 0, validateLV; // 游戏按钮的位置坐标
int i, j, k, n; // 消除方法控制
public void init() {
mainFrame = new JFrame("JKJ连连看");
thisContainer = mainFrame.getContentPane();
thisContainer.setLayout(new BorderLayout());
centerPanel = new JPanel();
southPanel = new JPanel();
northPanel = new JPanel();
thisContainer.add(centerPanel, "Center");
thisContainer.add(southPanel, "South");
thisContainer.add(northPanel, "North");
centerPanel.setLayout(new GridLayout(6, 5));
for (int cols = 0; cols < 6; cols++) {
for (int rows = 0; rows < 5; rows++) {
diamondsButton[cols][rows] = new JButton(String.valueOf(grid[cols + 1][rows + 1]));
diamondsButton[cols][rows].addActionListener(this);
centerPanel.add(diamondsButton[cols][rows]);
}
}
exitButton = new JButton("退出");
exitButton.addActionListener(this);
resetButton = new JButton("重列");
resetButton.addActionListener(this);
newlyButton = new JButton("再来一局");
newlyButton.addActionListener(this);
southPanel.add(exitButton);
southPanel.add(resetButton);
southPanel.add(newlyButton);
fractionLable.setText(String.valueOf(Integer.parseInt(fractionLable.getText())));
northPanel.add(fractionLable);
mainFrame.setBounds(280, 100, 500, 450);
mainFrame.setVisible(true);
mainFrame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
}
public void randomBuild() {
int randoms, cols, rows;
for (int twins = 1; twins <= 15; twins++) { // 一共15对button,30个
randoms = (int) (Math.random() * 25 + 1); // button上的数字
for (int alike = 1; alike <= 2; alike++) {
cols = (int) (Math.random() * 6 + 1);
rows = (int) (Math.random() * 5 + 1);
while (grid[cols][rows] != 0) { // 等于0说明这个空格有了button
cols = (int) (Math.random() * 6 + 1);
rows = (int) (Math.random() * 5 + 1);
}
this.grid[cols][rows] = randoms;
}
}
}
public void fraction() {
fractionLable.setText(String.valueOf(Integer.parseInt(fractionLable.getText()) + 100));
}
public void reload() {
int save[] = new int[30];
int n = 0, cols, rows;
int grid[][] = new int[8][7];
for (int i = 0; i <= 6; i++) {
for (int j = 0; j <= 5; j++) {
if (this.grid[i][j] != 0) {
save[n] = this.grid[i][j]; // 记下每个button的数字
n++; // 有几个没有消去的button
}
}
}
n = n - 1;
this.grid = grid;
while (n >= 0) { // 把没有消去的button重新放一次
cols = (int) (Math.random() * 6 + 1);
rows = (int) (Math.random() * 5 + 1);
while (grid[cols][rows] != 0) {
cols = (int) (Math.random() * 6 + 1);
rows = (int) (Math.random() * 5 + 1);
}
this.grid[cols][rows] = save[n];
n--;
}
mainFrame.setVisible(false);
pressInformation = false; // 这里一定要将按钮点击信息归为初始
init();
for (int i = 0; i < 6; i++) {
for (int j = 0; j < 5; j++) {
if (grid[i + 1][j + 1] == 0)
diamondsButton[i][j].setVisible(false);
}
}
}
public void estimateEven(int placeX, int placeY, JButton bz) {
if (pressInformation == false) {
x = placeX;
y = placeY;
secondMsg = grid[x][y];
secondButton = bz;
pressInformation = true;
} else {
x0 = x;
y0 = y;
fristMsg = secondMsg;
firstButton = secondButton;
x = placeX;
y = placeY;
secondMsg = grid[x][y];
secondButton = bz;
if (fristMsg == secondMsg && secondButton != firstButton) {
xiao();
}
}
}
public void xiao() { // 相同的情况下能不能消去。仔细分析,不一条条注释
if ((x0 == x && (y0 == y + 1 || y0 == y - 1)) || ((x0 == x + 1 || x0 == x - 1) && (y0 == y))) { // 判断是否相邻
remove();
} else {
for (j = 0; j < 7; j++) {
if (grid[x0][j] == 0) { // 判断和第一个按钮同行的哪个按钮为空
if (y < j) { // 第二个按钮在空按钮右边
for (i = y - 1; i >= j; i--) { // 检测从第二个按钮横向左边到空格所在列为止是否全是空格
if (grid[x][i] != 0) {
k = 0;
break; // 存在非空格的就退出,这一退出就不可能k==2了,所以就会到下而215行出同理的判断列
} else {
k = 1;
} // K=1说明全是空格通过了第一次验证,也就是从第二个按钮横向左边到空格所在列为止全是空格
}
if (k == 1) {
linePassOne(); // 进入第二次验证,也就是从第一个按钮到它同行的空格之间的空格判断
}
}
if (y > j) { // 第二个按钮在空按钮左边
for (i = y + 1; i <= j; i++) { // 检测从第二个按钮横向右边到空格所在列为止是否全是空格
if (grid[x][i] != 0) {
k = 0;
break;
} else {
k = 1;
}
}
if (k == 1) {
linePassOne();
}
}
if (y == j) { // 第二个按钮和空按钮同列
linePassOne();
}
}
if (k == 2) {
if (x0 == x) { // 第一,二按钮在同行
remove();
}
if (x0 < x) { // 第一按钮在第二按钮下边
for (n = x0; n <= x - 1; n++) { // 从空按钮竖向到第二个按钮所在行是否有按钮
if (grid[n][j] != 0) {
k = 0;
break;
}
if (grid[n][j] == 0 && n == x - 1) { // 没有按钮,说明这条路经就通了
remove();
}
}
}
if (x0 > x) { // 第一按钮在第二按钮上边
for (n = x0; n <= x + 1; n--) {
if (grid[n][j] != 0) {
k = 0;
break;
}
if (grid[n][j] == 0 && n == x + 1) {
remove();
}
}
}
}
}
for (i = 0; i < 8; i++) { // 列
if (grid[i][y0] == 0) { // 判断和第一个按钮同列的哪个按钮为空
if (x < i) { // 第二个按钮在这个空按钮的下面
for (j = x - 1; j >= i; j--) {
if (grid[j][y] != 0) {
k = 0;
break;
} else {
k = 1;
}
}
if (k == 1) {
rowPassOne();
}
}
if (x > i) { // 第二个按钮在这个空按钮的上面
for (j = x + 1; j <= i; j++) {
if (grid[j][y] != 0) {
k = 0;
break;
} else {
k = 1;
}
}
if (k == 1) {
rowPassOne();
}
}
if (x == i) { // 第二个按钮与这个空按钮同行
rowPassOne();
}
}
if (k == 2) {
if (y0 == y) { // 第二个按钮与第一个按钮同列
remove();
}
if (y0 < y) { // 第二个按钮在第一个按钮右边
for (n = y0; n <= y - 1; n++) {
if (grid[i][n] != 0) {
k = 0;
break;
}
if (grid[i][n] == 0 && n == y - 1) {
remove();
}
}
}
if (y0 > y) { // 第二个按钮在第一个按钮左边
for (n = y0; n <= y + 1; n--) {
if (grid[i][n] != 0) {
k = 0;
break;
}
if (grid[i][n] == 0 && n == y + 1) {
remove();
}
}
}
}
}
}
}
public void linePassOne() {
if (y0 < j) { // 第一按钮同行空按钮在左边
for (i = y0 - 1; i >= j; i--) { // 判断第一按钮同左侧空按钮之间有没按钮
if (grid[x0][i] != 0) {
k = 0;
break;
} else {
k = 2;
} // K=2说明通过了第二次验证
}
}
if (y0 > j) { // 第一按钮同行空按钮在右边
for (i = y0 + 1; i <= j; i++) {
if (grid[x0][i] != 0) {
k = 0;
break;
} else {
k = 2;
}
}
}
}
public void rowPassOne() {
if (x0 < i) { // 第一个按钮在与它同列的那个空按钮下面
for (j = x0 - 1; j >= i; j--) {
if (grid[j][y0] != 0) {
k = 0;
break;
} else {
k = 2;
}
}
}
if (x0 > i) { // 第一个按钮在与它同列的那个空按钮上面
for (j = x0 + 1; j <= i; j++) {
if (grid[j][y0] != 0) {
k = 0;
break;
} else {
k = 2;
}
}
}
}
public void remove() {
firstButton.setVisible(false);
secondButton.setVisible(false);
fraction();
pressInformation = false;
k = 0;
grid[x0][y0] = 0;
grid[x][y] = 0;
}
public void actionPerformed(ActionEvent e) {
if (e.getSource() == newlyButton) {
int grid[][] = new int[8][7];
this.grid = grid;
randomBuild();
mainFrame.setVisible(false);
pressInformation = false;
init();
}
if (e.getSource() == exitButton)
System.exit(0);
if (e.getSource() == resetButton)
reload();
for (int cols = 0; cols < 6; cols++) {
for (int rows = 0; rows < 5; rows++) {
if (e.getSource() == diamondsButton[cols][rows])
estimateEven(cols + 1, rows + 1, diamondsButton[cols][rows]);
}
}
}
public static void main(String[] args) {
LianLianKan llk = new LianLianKan();
llk.randomBuild();
llk.init();
}
}
求连连看源代码
连连看的代码(基本算法)加了部分注释
import java.awt.*;
import java.awt.event.*;
public class lianliankan implements ActionListener {
static String s = "no"; // 用来纪录点击按钮的信息
int x0 = 0, y0 = 0, x = 0, y = 0, n1 = 0, n2 = 0; // 用来纪录按钮的位置信息
Frame f, f1;
Button b1, b2, b3, b4, b5, b6, b7, b8, b9, b10; // 用比较笨的方法添加了
Button b11, b12, b13, b14, b15, b16, b17, b18; // 30个按钮来实现游戏界面
Button b19, b20, b21, b22, b23, b24, b25; // 可以用数组实现,这是本人
Button b26, b27, b28, b29, b30, bc; // 学java时,入门的联系,所以
Button b, ba, br, bt1, bt2; // 有些东西很业余!!嘻嘻
Panel p1, p2, p3;
TextField t; // 用来显示一些随机信息,方法是下面的guli().
Label l;
int d[][] = { // 用来和界面的按钮建立映射关系
{ 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0 }
};
public static void main(String[] args) {
lianliankan t = new lianliankan();
t.suiji();
t.go();
}
public void actionPerformed(ActionEvent e) // 再来一次按钮的响应事件。
{
int d[][] = {
{ 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0 }
};
this.d = d;
suiji();
f.setVisible(false);
f1.setVisible(false);
s = "no";
go();
}
public void go() // 初始化界面
{
l = new Label("亲爱的玩家,");
f = new Frame("连连看");
t = new TextField();
p2 = new Panel();
p1 = new Panel();
p3 = new Panel();
bc = new Button("退出");
br = new Button("重列");
b = new Button();
b1 = new Button(String.valueOf(d[1][1]));
b2 = new Button(String.valueOf(d[1][2]));
b3 = new Button(String.valueOf(d[1][3]));
b4 = new Button(String.valueOf(d[1][4]));
b5 = new Button(String.valueOf(d[1][5]));
b6 = new Button(String.valueOf(d[2][1]));
b7 = new Button(String.valueOf(d[2][2]));
b8 = new Button(String.valueOf(d[2][3]));
b9 = new Button(String.valueOf(d[2][4]));
b10 = new Button(String.valueOf(d[2][5]));
b11 = new Button(String.valueOf(d[3][1]));
b12 = new Button(String.valueOf(d[3][2]));
b13 = new Button(String.valueOf(d[3][3]));
b14 = new Button(String.valueOf(d[3][4]));
b15 = new Button(String.valueOf(d[3][5]));
b16 = new Button(String.valueOf(d[4][1]));
b17 = new Button(String.valueOf(d[4][2]));
b18 = new Button(String.valueOf(d[4][3]));
b19 = new Button(String.valueOf(d[4][4]));
b20 = new Button(String.valueOf(d[4][5]));
b21 = new Button(String.valueOf(d[5][1]));
b22 = new Button(String.valueOf(d[5][2]));
b23 = new Button(String.valueOf(d[5][3]));
b24 = new Button(String.valueOf(d[5][4]));
b25 = new Button(String.valueOf(d[5][5]));
b26 = new Button(String.valueOf(d[6][1]));
b27 = new Button(String.valueOf(d[6][2]));
b28 = new Button(String.valueOf(d[6][3]));
b29 = new Button(String.valueOf(d[6][4]));
b30 = new Button(String.valueOf(d[6][5]));
p3.setLayout(null);
p1.setSize(250, 300);
p2.setSize(100, 40);
p3.setSize(300, 30);
t.setSize(60, 30);
l.setSize(70, 30);
p1.setLayout(new GridLayout(6, 5));
p1.setBackground(Color.pink);
p1.setLocation(100, 100);
p2.setLocation(0, 400);
p3.setLocation(50, 50);
t.setLocation(230, 2);
l.setLocation(150, 2);
bc.setLocation(0, 40);
br.setLocation(0, 100);
f.add(p1);
f.add(p2);
f.add(p3);
p3.add(l);
p3.add(t);
p2.add(bc);
p2.add(br);
p1.add(b1);
p1.add(b2);
p1.add(b3);
p1.add(b4);
p1.add(b5);
p1.add(b6);
p1.add(b7);
p1.add(b8);
p1.add(b9);
p1.add(b10);
p1.add(b11);
p1.add(b12);
p1.add(b13);
p1.add(b14);
p1.add(b15);
p1.add(b16);
p1.add(b17);
p1.add(b18);
p1.add(b19);
p1.add(b20);
p1.add(b21);
p1.add(b22);
p1.add(b23);
p1.add(b24);
p1.add(b25);
p1.add(b26);
p1.add(b27);
p1.add(b28);
p1.add(b29);
p1.add(b30);
f.pack();
f.setBounds(280, 100, 500, 450);
f.setResizable(false);
f.setVisible(true);
bc.addMouseListener(new MouseAdapter() {
public void mouseClicked(MouseEvent e) {
ex();
}
});
br.addMouseListener(new MouseAdapter() {
public void mouseClicked(MouseEvent e) {
chonglie();
}
});
b1.addMouseListener(new MouseAdapter() {
public void mouseClicked(MouseEvent e) {
wei(1, 1, b1);
}
});
b2.addMouseListener(new MouseAdapter() {
public void mouseClicked(MouseEvent e) {
wei(1, 2, b2);
}
});
b3.addMouseListener(new MouseAdapter() {
public void mouseClicked(MouseEvent e) {
wei(1, 3, b3);
}
});
b4.addMouseListener(new MouseAdapter() {
public void mouseClicked(MouseEvent e) {
wei(1, 4, b4);
}
});
b5.addMouseListener(new MouseAdapter() {
public void mouseClicked(MouseEvent e) {
wei(1, 5, b5);
}
});
b6.addMouseListener(new MouseAdapter() {
public void mouseClicked(MouseEvent e) {
wei(2, 1, b6);
}
});
b7.addMouseListener(new MouseAdapter() {
public void mouseClicked(MouseEvent e) {
wei(2, 2, b7);
}
});
b8.addMouseListener(new MouseAdapter() {
public void mouseClicked(MouseEvent e) {
wei(2, 3, b8);
}
});
b9.addMouseListener(new MouseAdapter() {
public void mouseClicked(MouseEvent e) {
wei(2, 4, b9);
}
});
b10.addMouseListener(new MouseAdapter() {
public void mouseClicked(MouseEvent e) {
wei(2, 5, b10);
}
});
b11.addMouseListener(new MouseAdapter() {
public void mouseClicked(MouseEvent e) {
wei(3, 1, b11);
}
});
b12.addMouseListener(new MouseAdapter() {
public void mouseClicked(MouseEvent e) {
wei(3, 2, b12);
}
});
b13.addMouseListener(new MouseAdapter() {
public void mouseClicked(MouseEvent e) {
wei(3, 3, b13);
}
});
b14.addMouseListener(new MouseAdapter() {
public void mouseClicked(MouseEvent e) {
wei(3, 4, b14);
}
});
b15.addMouseListener(new MouseAdapter() {
public void mouseClicked(MouseEvent e) {
wei(3, 5, b15);
}
});
b16.addMouseListener(new MouseAdapter() {
public void mouseClicked(MouseEvent e) {
wei(4, 1, b16);
}
});
b17.addMouseListener(new MouseAdapter() {
public void mouseClicked(MouseEvent e) {
wei(4, 2, b17);
}
});
b