本文目录一览：

1. C语言个人所得税计算系统
2. C语言计算个人所得税 编程
3. C语言，个人所得税计算，求大神回答- -悬赏有点少

C语言个人所得税计算系统

这样看能不能符合你的要求，说实话，分好少！不行的话可以追问

include<stdio.h>
void main()
{
    double insure1=0.18; //个人承担保险金
    double insure2=0.29; //他人承担保险金
    int charge=3500; //费用扣除额
    int pay=0; //基本工资
    int fast=0; //速算金额
    double cass=0.0; //税率
    double ratepaying=0.0; //应纳税所得额
    int type; //是又个人承担的，还是他人代付
    double sum=0.0;
    printf("请输入你当月取得的工资收入:%d",pay);
    scanf("%d",&pay);
    printf("个人所得税是由谁承担？(0:自己，1:他人代付)：%d",type);
    scanf("%d",&type);
    if(type==0)
    {
        ratepaying=pay-pay*insure-charge;
        if(ratepaying<=1500)
        {
            cass=0.03;
            fast=0;
        }
        else if(ratepaying>1500 && ratepaying<=4500)
        {
            cass=0.1;
            fast=105;
        }
        else if(ratepaying>4500 && ratepaying<=9000)
        {
            cass=0.2;
            fast=555;
        }
        else if(ratepaying>9000 && ratepaying<=35000)
        {
            cass=0.25;
            fast=1005;
        }
        else if(ratepaying>35000 && ratepaying<=55000)
        {
            cass=0.3;
            fast=2755;
        }
        else if(ratepaying>55000 && ratepaying<=80000)
        {
            cass=0.35;
            fast=5505;
        }
        else
        {
            cass=0.45;
            fast=13505;
        }
        sum=ratepaying*cass-fast;
        printf("应纳个人所得税税额为:%.2lf",sum);
    }
    else
    {
        ratepaying=pay-pay*insure-charge;
        if(ratepaying<=1455)
        {
            cass=0.03;
            fast=0;
        }
        else if(ratepaying>1455 && ratepaying<=4155)
        {
            cass=0.1;
            fast=105;
        }
        else if(ratepaying>4155 && ratepaying<=7755)
        {
            cass=0.2;
            fast=555;
        }
        else if(ratepaying>7755 && ratepaying<=27255)
        {
            cass=0.25;
            fast=1005;
        }
        else if(ratepaying>27255 && ratepaying<=41255)
        {
            cass=0.3;
            fast=2755;
        }
        else if(ratepaying>41255 && ratepaying<=57505)
        {
            cass=0.35;
            fast=5505;
        }
        else
        {
            cass=0.45;
            fast=13505;
        }
        sum=ratepaying*cass-fast;
        printf("应纳个人所得税税额为:%.2lf",sum);
    }
}

C语言计算个人所得税 编程

#include <stdio.h>
#include <stdlib.h>
int jishu(double x)
{
    if(0 < x && x <= 500)
        return 1;
    else if(500 < x && x <= 2000)
        return 2;
    else if(2000 < x && x <= 5000)
        return 3;
    else if(5000 < x && x <= 20000)
        return 4;
    else if(20000 < x && x <= 40000)
        return 5;
    else if(40000 < x && x <= 60000)
        return 6;
    else if(60000 < x && x <= 80000)
        return 7;
    else if(80000 < x && x <= 100000)
        return 8;
    else
        return 9;
}
main()
{
    double rate[10]={0.0,0.05,0.1,0.15,0.2,0.25,0.3,0.35,0.4,0.45};
    int a[10]={0,0,25,125,375,1375,3375,6375,10375,15375};
    double n,m,l;
    int i;
    printf("请输入工资：");
    scanf("%lf",&l);
    if(l <= 3500)
        printf("您不用交税\n");
    else
    {
        n=l-3500.0;
        i=jishu(n);
        m=n*rate[i]-a[i];
        printf("应缴个人所得税：%.2lf\n实发工资额：%.2lf\n",m,l-m);
    }
}

这是按你说的计算方法

C语言，个人所得税计算，求大神回答- -悬赏有点少

#include<stdio.h>
double IIT(int money, int nation)
{
    double iit = money;
    switch(nation)
    {
        case 1 : iit = money - 1000 - 3500; break;
        case 0 : iit = money - 1000 - 4800; break;
        default: printf("输入有误！\n");
    }
    if(iit <= 1500) iit = iit * 0.03;
    else if(iit > 1500 && iit <= 4500) iit = (iit * 0.1 - 105);
    else if(iit > 4500 && iit <= 9000) iit = (iit * 0.2 - 555);
    else if(iit > 9000 && iit <= 35000) iit = (iit * 0.25 - 1005);
    else if(iit > 35000 && iit <= 55000) iit = (iit * 0.3 - 2755);
    else if(iit > 55000 && iit <= 80000) iit = (iit * 0.35 - 5505);
    else iit = (iit * 0.45 - 13505);
    return iit;
}
int main()
{
    int money, nation;
    printf("请确定你的国籍： 1.中国 0.外籍\n");
    scanf("%d", &nation);
    printf("请输入您的工资： ");
    scanf("%d", &money);
    if(nation == 1)
    {
        if(money <= 4500)
            printf("您不需要缴纳个人所得税。\n");
        else
            printf("您要缴纳的个人所得税为： %.0f", IIT(money, nation));
    }
    if(nation == 0)
    {
        if(money <= 5800)
            printf("您不需要缴纳个人所得税。\n");
        else
            printf("您要缴纳的个人所得税为： %.0f", IIT(money, nation));
    }
    return 0;
}