本文目录一览：
用C语言怎么将公历日期转化为农历日期?
其实很简单，你的程序中定义一些数组，保存一些重要参数即可，下面是JAVASCRIPT的，看懂了你就可以用C来写：
var lunarInfo=new Array(
0x04bd8,0x04ae0,0x0a570,0x054d5,0x0d260,0x0d950,0x16554,0x056a0,0x09ad0,0x055d2,
0x04ae0,0x0a5b6,0x0a4d0,0x0d250,0x1d255,0x0b540,0x0d6a0,0x0ada2,0x095b0,0x14977,
0x04970,0x0a4b0,0x0b4b5,0x06a50,0x06d40,0x1ab54,0x02b60,0x09570,0x052f2,0x04970,
0x06566,0x0d4a0,0x0ea50,0x06e95,0x05ad0,0x02b60,0x186e3,0x092e0,0x1c8d7,0x0c950,
0x0d4a0,0x1d8a6,0x0b550,0x056a0,0x1a5b4,0x025d0,0x092d0,0x0d2b2,0x0a950,0x0b557,
0x06ca0,0x0b550,0x15355,0x04da0,0x0a5d0,0x14573,0x052d0,0x0a9a8,0x0e950,0x06aa0,
0x0aea6,0x0ab50,0x04b60,0x0aae4,0x0a570,0x05260,0x0f263,0x0d950,0x05b57,0x056a0,
0x096d0,0x04dd5,0x04ad0,0x0a4d0,0x0d4d4,0x0d250,0x0d558,0x0b540,0x0b5a0,0x195a6,
0x095b0,0x049b0,0x0a974,0x0a4b0,0x0b27a,0x06a50,0x06d40,0x0af46,0x0ab60,0x09570,
0x04af5,0x04970,0x064b0,0x074a3,0x0ea50,0x06b58,0x055c0,0x0ab60,0x096d5,0x092e0,
0x0c960,0x0d954,0x0d4a0,0x0da50,0x07552,0x056a0,0x0abb7,0x025d0,0x092d0,0x0cab5,
0x0a950,0x0b4a0,0x0baa4,0x0ad50,0x055d9,0x04ba0,0x0a5b0,0x15176,0x052b0,0x0a930,
0x07954,0x06aa0,0x0ad50,0x05b52,0x04b60,0x0a6e6,0x0a4e0,0x0d260,0x0ea65,0x0d530,
0x05aa0,0x076a3,0x096d0,0x04bd7,0x04ad0,0x0a4d0,0x1d0b6,0x0d250,0x0d520,0x0dd45,
0x0b5a0,0x056d0,0x055b2,0x049b0,0x0a577,0x0a4b0,0x0aa50,0x1b255,0x06d20,0x0ada0)
//====================================== 传回农历 y年的总天数
function lYearDays(y) {
var i, sum = 348
for(i=0x8000; i0x8; i=1) sum += (lunarInfo[y-1900] i)? 1: 0
return(sum+leapDays(y))
}
//====================================== 传回农历 y年闰月的天数
function leapDays(y) {
if(leapMonth(y)) return((lunarInfo[y-1900] 0x10000)? 30: 29)
else return(0)
}
//====================================== 传回农历 y年闰哪个月 1-12 , 没闰传回 0
function leapMonth(y) {
return(lunarInfo[y-1900] 0xf)
}
//====================================== 传回农历 y年m月的总天数
function monthDays(y,m) {
return( (lunarInfo[y-1900] (0x10000m))? 30: 29 )
}
用C语言怎么编写万年历
1、首先下载安装Notepad++，这是一款免费的且能够编辑C语言的软件。
2、然后下载安装tdm-gcc，这是为了给电脑配置环境变量，以便能够编译C语言的。
3、在安装完以上两款软件后，还要配置一下环境变量。
4、然后开始编辑C语言万年历，首先要判断一个年份是闰年还是平年，用一个子程序来做：
5、然后就开始写主程序：首先用scanf得到一个年份，在判断这个年份是平年还是闰年后用printf在CMD中打出来。
6、在编写完成后，在Notepad++界面下按下F5，在输入框中输入：
cmd /k gcc -o "$(CURRENT_DIRECTORY)\$(NAME_PART).exe" "$(FULL_CURRENT_PATH)" CLS "$(CURRENT_DIRECTORY)\$(NAME_PART).exe" PAUSE EXIT
7、最后点击运行，会弹出CMD，在里面输入年份后回车：例如输入2017，然后回车，就会生成2017年的万年历了！
C语言编程：输入任意一个年份和月份，按格式输出该月份的公历日历
if(month==4||6||9||11)
if(month==1||3||5||7||8||10||12)
这种写法是错误的。
应该这样写
if(month==4||month==6||month==9||month==11)
if(month==1||month==3||month==5||month==7||month==8||month==10||month==12)
另外，其实你可以不这么写，太多了，可以用
switch..case
switch(month)
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
day=31;break;
case 4:
case 6:
case 9:
case 11:
day=30;break;
case 2:
if()...
（c语言实现）打印指定年份的公历表和农历表
#include stdlib.h
#include stdio.h
#include conio.h
int IsLeapYear(int);
main()
{
int i;
int day;
int year;
int temp;
int temp_i;
long int Year_days = 0;
int Year_Start = 1;
int Per_Year_Days;
int month_day[]={31,28,31,30,31,30,31,31,30,31,30,31,29};
printf("输入年份: "); /*从键盘输入年份*/
scanf("%d",year);
while(Year_Start year)
{
if( IsLeapYear( Year_Start ) ) /*判断输入的年份是否为闰年*/
Per_Year_Days = 366;
else
Per_Year_Days = 365;
Year_days = Year_days + Per_Year_Days;
Year_Start++;
} /*这个while循环计算从1到输入的年份共有多少天*/
for( temp = 1; temp =12; temp++ )
{ /*这个for循环打印出该年每个月的日历*/
switch( temp )
{
case 1:
printf(" January(%d)\n",year);
break;
case 2:
printf(" February(%d)\n",year);
break;
case 3:
printf(" March(%d)\n",year);
break;
case 4:
printf(" April(%d)\n",year);
break;
case 5:
printf(" May(%d)\n",year);
break;
case 6:
printf(" June(%d)\n",year);
break;
case 7:
printf(" July(%d)\n",year);
break;
case 8:
printf(" August(%d)\n",year);
break;
case 9:
printf(" September(%d)\n",year);
break;
case 10:
printf(" October(%d)\n",year);
break;
case 11:
printf(" November(%d)\n",year);
break;
case 12:
printf(" December(%d)\n",year);
break;
}
i = Year_days % 7;
printf("Mon Tue Wed Thu Fri Sat Sun\n");
if( i != 0 )
for( temp_i = 0; temp_i i; temp_i++)
printf(" ");
day = 1;
if( IsLeapYear(year) temp == 2) /*如果是闰年的2月*/
while( day = month_day[12] )
{
if( day 1 )
if( Year_days % 7 == 0 )
printf("\n");
if( day = 10 )
printf("%-4d",day);
else
printf("%-4d",day);
Year_days++;
day++;
}
else /*不是闰年*/
while (day = month_day[temp-1])
{
if( day 1 )
if( Year_days % 7 == 0 )
printf("\n");
if( day =10 )
printf("%-4d",day);
else
printf("%-4d",day);
Year_days++;
day++;
}
printf("\n");
if( getch() == 'q' ) /*输入Q结束*/
exit(0);
}
getch();
}
int IsLeapYear( int year ) /*判断是否为闰年*/
{
if ((year %4 == 0) (year % 100 != 0) ||
(year % 400 == 0) )
return 1;
else
return 0;
}
