本文目录一览：

1、c语言编程 赋值错误
2、C语言 关于赋值错误的问题
3、C语言结构赋值报错。
4、C语言 数组指针赋值出错

c语言编程 赋值错误

scanf函数要求输入时与双引号内的格式完全一致，例如你写的

scanf("%d,%d,%d,%d",a,b,c,d);

输入时就应该写

1,2,3,4

这样的（注意逗号要用英文的逗号）

C语言 关于赋值错误的问题

if((a=b)((b-a+1)=N)(((a+b)*(b-a+1))/2=M))

这句语句错了，我不知道你是不是想写成 (((a+b)*(b-a+1))/2==M)（= 变成 ==） 这个的错误是，等号前面是表达式，表达式的结果是一个临时变量，你把 M 赋值给一个临时变量，肯定错了。临时变量不能做左值。 要不改成 ==，表示相等，如果就是赋值，把 M 写前面就可以了，把运算的值赋给 M。

C语言结构赋值报错。

您好哦，这样的：

main(void)
{
    struct convert
    {
        double C[3][3];
    };
    struct convert con[24] =
    {
        {1,0.0,0.0,0.0,1.0,0.0,0.0,0.0,1.0},
        {0.0,0.0,-1.0,0.0,-1.0,0.0,-1.0,0.0,0.0},
        {0.0,0.0,-1.0,0.0,1.0,0.0,1.0,0.0,0.0},
        {-1.0,0.0,0.0,0.0,1.0,0.0,0.0,0.0,-1.0},
        {0.0,0.0,1.0,0.0,1.0,0.0,-1.0,0.0,0.0},
        {1.0,0.0,0.0,0.0,0.0,-1.0,0.0,1.0,0.0},
        {1.0,0.0,0.0,0.0,-1.0,0.0,0.0,0.0,-1.0},
        {1.0,0.0,0.0,0.0,0.0,1.0,0.0,-1.0,0.0},
        {0.0,-1.0,0.0,1.0,0.0,0.0,0.0,0.0,1.0},
        {-1.0,0.0,0.0,0.0,-1.0,0.0,0.0,0.0,1.0},
        {0.0,1.0,0.0,-1.0,0.0,0.0,0.0,0.0,1.0},
        {0.0,0.0,1.0,1.0,0.0,0.0,0.0,1.0,0.0},
        {0.0,1.0,0.0,0.0,0.0,1.0,1.0,0.0,0.0},
        {0.0,0.0,-1.0,-1.0,0.0,0.0,0.0,1.0,0.0},
        {0.0,-1.0,0.0,0.0,0.0,1.0,-1.0,0.0,0.0},
        {0.0,1.0,0.0,0.0,0.0,-1.0,-1.0,0.0,0.0},
        {0.0,0.0,-1.0,1.0,0.0,0.0,0.0,-1.0,0.0},
        {0.0,0.0,1.0,-1.0,0.0,0.0,0.0,-1.0,0.0},
        {0.0,-1.0,0.0,0.0,0.0,-1.0,1.0,0.0,0.0},
        {0.0,1.0,0.0,1.0,0.0,0.0,0.0,0.0,-1.0},
        {-1.0,0.0,0.0,0.0,0.0,1.0,0.0,1.0,0.0},
        {0.0,0.0,1.0,0.0,-1.0,0.0,1.0,0.0,0.0},
        {0.0,-1.0,0.0,-1.0,0.0,0.0,0.0,0.0,-1.0},
        {-1.0,0.0,0.0,0.0,0.0,-1.0,0.0,-1.0,0.0}
    };
    return 0;
}

C语言 数组指针赋值出错

char *string[20]; 这样声明的是一个名为 string 的数组，这个数组有 20 个元素，每一个元素都是一个 char * 型指针。所以数组里存放的是“指针”，只是个 4 字节变量，它还没有指向，就不能用 string[i][j]='\0'; 这种办法给它的指向目标赋值。要么直接把 char *string[20]; 改成 char string[20][100];（可以存放 20 个长 99 的字符串），要么在 char *string[20]; 后用 malloc 等函数分别为 20 个指针分配空间。